audk/ArmPkg/Library/CompilerIntrinsicsLib/AArch64/memcpy.S

126 lines
4.3 KiB
ArmAsm

/*
* Copyright (c) 2011 - 2013, ARM Ltd
* All rights reserved.
*
* Redistribution and use in source and binary forms, with or without
* modification, are permitted provided that the following conditions
* are met:
* 1. Redistributions of source code must retain the above copyright
* notice, this list of conditions and the following disclaimer.
* 2. Redistributions in binary form must reproduce the above copyright
* notice, this list of conditions and the following disclaimer in the
* documentation and/or other materials provided with the distribution.
* 3. The name of the company may not be used to endorse or promote
* products derived from this software without specific prior written
* permission.
*
* THIS SOFTWARE IS PROVIDED BY ARM LTD ``AS IS'' AND ANY EXPRESS OR IMPLIED
* WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES OF
* MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE DISCLAIMED.
* IN NO EVENT SHALL ARM LTD BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL,
* SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT LIMITED
* TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, DATA, OR
* PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY THEORY OF
* LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT (INCLUDING
* NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF THIS
* SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
*/
.text
.align 2
GCC_ASM_EXPORT(memcpy)
// Taken from Newlib BSD implementation.
ASM_PFX(memcpy):
// Copy dst to x6, so we can preserve return value.
mov x6, x0
// NOTE: although size_t is unsigned, this code uses signed
// comparisons on x2 so relies on nb never having its top bit
// set. In practice this is not going to be a real problem.
// Require at least 64 bytes to be worth aligning.
cmp x2, #64
blt qwordcopy
// Compute offset to align destination to 16 bytes.
neg x3, x0
and x3, x3, 15
cbz x3, blockcopy // offset == 0 is likely
// We know there is at least 64 bytes to be done, so we
// do a 16 byte misaligned copy at first and then later do
// all 16-byte aligned copies. Some bytes will be copied
// twice, but there's no harm in that since memcpy does not
// guarantee correctness on overlap.
sub x2, x2, x3 // nb -= offset
ldp x4, x5, [x1]
add x1, x1, x3
stp x4, x5, [x6]
add x6, x6, x3
// The destination pointer is now qword (16 byte) aligned.
// (The src pointer might be.)
blockcopy:
// Copy 64 bytes at a time.
subs x2, x2, #64
blt 3f
2: subs x2, x2, #64
ldp x4, x5, [x1,#0]
ldp x8, x9, [x1,#16]
ldp x10,x11,[x1,#32]
ldp x12,x13,[x1,#48]
add x1, x1, #64
stp x4, x5, [x6,#0]
stp x8, x9, [x6,#16]
stp x10,x11,[x6,#32]
stp x12,x13,[x6,#48]
add x6, x6, #64
bge 2b
// Unwind pre-decrement
3: add x2, x2, #64
qwordcopy:
// Copy 0-48 bytes, 16 bytes at a time.
subs x2, x2, #16
blt tailcopy
2: ldp x4, x5, [x1],#16
subs x2, x2, #16
stp x4, x5, [x6],#16
bge 2b
// No need to unwind the pre-decrement, it would not change
// the low 4 bits of the count. But how likely is it for the
// byte count to be multiple of 16? Is it worth the overhead
// of testing for x2 == -16?
tailcopy:
// Copy trailing 0-15 bytes.
tbz x2, #3, 1f
ldr x4, [x1],#8 // copy 8 bytes
str x4, [x6],#8
1:
tbz x2, #2, 1f
ldr w4, [x1],#4 // copy 4 bytes
str w4, [x6],#4
1:
tbz x2, #1, 1f
ldrh w4, [x1],#2 // copy 2 bytes
strh w4, [x6],#2
1:
tbz x2, #0, return
ldrb w4, [x1] // copy 1 byte
strb w4, [x6]
return:
// This is the only return point of memcpy.
ret