Make container service color deterministic, remove red from chosen colors

Signed-off-by: Anthony Lai <anthonyjlai@gmail.com>
This commit is contained in:
Anthony Lai 2019-11-03 22:54:44 +00:00
parent fa34ee7362
commit 802fa20228
2 changed files with 6 additions and 3 deletions

View File

@ -41,9 +41,9 @@ for (name, code) in get_pairs():
def rainbow():
cs = ['cyan', 'yellow', 'green', 'magenta', 'red', 'blue',
cs = ['cyan', 'yellow', 'green', 'magenta', 'blue',
'intense_cyan', 'intense_yellow', 'intense_green',
'intense_magenta', 'intense_red', 'intense_blue']
'intense_magenta', 'intense_blue']
for c in cs:
yield globals()[c]

View File

@ -134,7 +134,10 @@ def build_thread(container, presenter, queue, log_args):
def build_thread_map(initial_containers, presenters, thread_args):
return {
container.id: build_thread(container, next(presenters), *thread_args)
for container in initial_containers
# Container order is unspecified, so they are sorted by name in order to make
# container:presenter (log color) assignment deterministic when given a list of containers
# with the same names.
for container in sorted(initial_containers, key=lambda c: c.name)
}