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Spike: Start linked containers on `fig run` by default 

Signed-off-by: Chris Corbyn <chris@w3style.co.uk>
This commit is contained in:
d11wtq 2014-06-08 06:32:42 +00:00 committed by Chris Corbyn
parent b081077f2b
commit b672861ffd
1 changed files with 18 additions and 13 deletions
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31
fig/cli/main.py
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@ -202,27 +202,29 @@ class TopLevelCommand(Command):
$ fig run web python manage.py shell
Note that by default this will not start any services that the
command's service links to. So if, for example, your one-off command
talks to your database, you will need to either run `fig up -d db`
first, or use `fig run --up SERVICE COMMAND [ARGS...]`.
By default, linked services will be started, unless they are already
running. If you do not want to start linked services, use
`fig run --no-links SERVICE COMMAND [ARGS...]`.
Usage: run [options] SERVICE COMMAND [ARGS...]
Options:
-d Detached mode: Run container in the background, print new
container name
-T Disable pseudo-tty allocation. By default `fig run`
allocates a TTY.
--rm Remove container after run. Ignored in detached mode.
--up Also start services that the command's service links to
-d Detached mode: Run container in the background, print
new container name.
-T Disable pseudo-tty allocation. By default `fig run`
allocates a TTY.
--rm Remove container after run. Ignored in detached mode.
--no-links Don't start linked services.
"""
if options['--up']:
self.up({'-d': True, 'SERVICE': None})
service = self.project.get_service(options['SERVICE'])
if not options['--no-links']:
self.up({
'-d': True,
'SERVICE': self._get_linked_service_names(service)
})
tty = True
if options['-d'] or options['-T'] or not sys.stdin.isatty():
tty = False
@ -338,5 +340,8 @@ class TopLevelCommand(Command):
raw=raw,
)
def _get_linked_service_names(self, service):
return [s.name for (s, _) in service.links]
def list_containers(containers):
return ", ".join(c.name for c in containers)