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Even if a double represents an integer value, it might not be safe to cast it to long long as it may overflow the type. Instead just use print the double value with 0 decimals using std::setprecision. Before: <1> => 18446744073709551616.to_string() "-9223372036854775808" After: <1> => 18446744073709551616.to_string() "18446744073709551616"
47 lines
881 B
C++
47 lines
881 B
C++
/* Icinga 2 | (c) 2012 Icinga GmbH | GPLv2+ */
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#include "base/convert.hpp"
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#include "base/datetime.hpp"
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#include <boost/lexical_cast.hpp>
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#include <iomanip>
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using namespace icinga;
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String Convert::ToString(const String& val)
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{
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return val;
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}
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String Convert::ToString(const Value& val)
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{
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return val;
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}
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String Convert::ToString(double val)
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{
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double integral;
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double fractional = std::modf(val, &integral);
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std::ostringstream msgbuf;
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if (fractional == 0) {
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msgbuf << std::setprecision(0);
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}
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msgbuf << std::fixed << val;
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return msgbuf.str();
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}
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double Convert::ToDateTimeValue(double val)
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{
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return val;
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}
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double Convert::ToDateTimeValue(const Value& val)
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{
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if (val.IsNumber())
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return val;
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else if (val.IsObjectType<DateTime>())
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return static_cast<DateTime::Ptr>(val)->GetValue();
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else
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BOOST_THROW_EXCEPTION(std::invalid_argument("Not a DateTime value."));
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}
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