Improve function to search for kernels on disk and checking results

This commit is contained in:
mboelen 2014-10-14 10:03:29 +02:00
parent f5399981c2
commit 4fa5139bfa
1 changed files with 8 additions and 7 deletions

View File

@ -490,21 +490,24 @@
logtext "Result: /boot/vmlinuz not on disk, trying to find /boot/vmlinuz*"
# Extra current kernel version and replace dashes to allow numeric sort later on
MYKERNEL=`uname -r | sed 's/\.[a-z].*.//g' | sed 's/-[a-z].*.//g' | sed 's/-/./g'`
logtext "Result: using ${MYKERNEL} as my kernel version (stripped)"
FIND=`ls /boot/vmlinuz* 2> /dev/null`
if [ ! "${FIND}" = "" ]; then
# Display kernels, extract version numbers and sort them numeric per column (up to 6 numbers)
KERNELS=`ls /boot/vmlinuz* | sed 's/vmlinuz-//' | sed 's/\.[a-z].*.//g' | sed 's/-[a-z].*.//g' | sed 's./boot/..' | sed 's/-/./g' | sort -n -k1,1 -k2,2 -k3,3 -k4,4 -k5,5 -k6,6 -t \.`
elif [ ! `ls /boot/kernel* 2> /dev/null` = "" ]; then
# Display kernels, extract version numbers and sort them numeric per column (up to 6 numbers)
# Examples:
# /boot/kernel-genkernel-x86_64-3.14.14-gentoo
KERNELS=`ls /boot/kernel* | awk -F- '{ if ($2=="genkernel") { print $4 }}' | grep "^[0-9]" | sort -n -k1,1 -k2,2 -k3,3 -k4,4 -k5,5 -k6,6 -t \.`
logtext "Result: using ${MYKERNEL} as my kernel version (stripped)"
else
ReportException "${TEST_NO}:2" "Can not find any vmlinuz or kernel files in /boot, which is unexpected"
fi
if [ ! "${KERNELS}" = "" ]; then
FOUND_KERNEL=0
for I in ${KERNELS}; do
if [ ${FOUND_KERNEL} -eq 1 ]; then
# Check if we already found a kernel and it is not equal to what we run (e.g. double versions may exist)
if [ ${FOUND_KERNEL} -eq 1 -a ! "${MYKERNEL}" = "${I}" ]; then
logtext "Result: found a kernel (${I}) later than running one (${MYKERNEL})"
REBOOT_NEEDED=1
fi
@ -525,8 +528,6 @@
REBOOT_NEEDED=0
fi
fi
else
ReportException "${TEST_NO}:2" "Can not find any vmlinuz or kernel files in /boot, which is unexpected"
fi
fi
# No files in /boot