[FILE-6430] Don't grep nonexistant modprobe.d files

We don't want to grep files in modprobe.d when dir is empty. Uses same approach
as in USB-1000.
This commit is contained in:
Kepi 2020-07-02 18:22:03 +02:00
parent 1da058d6de
commit 9d52395952
1 changed files with 9 additions and 6 deletions

View File

@ -830,12 +830,15 @@
AddHP 3 3 AddHP 3 3
if IsDebug; then Display --indent 6 --text "- Module ${FS} not present in the kernel" --result OK --color GREEN; fi if IsDebug; then Display --indent 6 --text "- Module ${FS} not present in the kernel" --result OK --color GREEN; fi
fi fi
FIND1=$(${EGREPBINARY} "blacklist ${FS}" ${ROOTDIR}etc/modprobe.d/* | ${GREPBINARY} -v "#") FIND=$(${LSBINARY} ${ROOTDIR}etc/modprobe.d/* 2> /dev/null)
FIND2=$(${EGREPBINARY} "install ${FS} /bin/true" ${ROOTDIR}etc/modprobe.d/* | ${GREPBINARY} -v "#") if [ -n "${FIND}" ]; then
if [ -n "${FIND1}" ] || [ -n "${FIND2}" ]; then FIND1=$(${EGREPBINARY} "blacklist ${FS}" ${ROOTDIR}etc/modprobe.d/* | ${GREPBINARY} -v "#")
Display --indent 4 --text "- Module $FS is blacklisted" --result "OK" --color GREEN FIND2=$(${EGREPBINARY} "install ${FS} /bin/true" ${ROOTDIR}etc/modprobe.d/* | ${GREPBINARY} -v "#")
LogText "Result: module ${FS} is blacklisted" if [ -n "${FIND1}" ] || [ -n "${FIND2}" ]; then
fi Display --indent 4 --text "- Module $FS is blacklisted" --result "OK" --color GREEN
LogText "Result: module ${FS} is blacklisted"
fi
fi
done done
if [ ${FOUND} -eq 1 ]; then if [ ${FOUND} -eq 1 ]; then
Display --indent 4 --text "- Discovered kernel modules: ${AVAILABLE_MODPROBE_FS}" Display --indent 4 --text "- Discovered kernel modules: ${AVAILABLE_MODPROBE_FS}"