mirror of
https://github.com/notepad-plus-plus/notepad-plus-plus.git
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Update with https://www.scintilla.org/scintilla521.zip https://www.scintilla.org/lexilla515.zip - fix setting to bring Scintilla::PositionCR from ScintillaStructures.h inline with Sci_Position.h Sci_PositionCR - add workaround to enable lexer for searchResult commented out SCI_SETILEXER call on searchResult to get one result which is correctly handled by the lexer, added comment about the current problem with property @MarkingsStruct which seems to disappear after call to SCI_SETILEXER or CreateLexer - corrected usage of ObjC lexer - removed unnecessary filter stuff - use own sections for scintilla and lexilla build targets and allow parallel builds - as libscilex is no longer existing, changed to libscintilla - adapt makefiles and cmake - use VS2019 - started simple changes for createlexer adaptations, nullpointercheck missing on return of lexer name from deprecated LexerNameFromID -> undefined behaviour - movement from id -> lexer name, mostly done via LexerNameFromID + switching off corresponding compiler warning - changed to SCI_SETILEXER from SCI_SETLEXER, SCI_SETLEXERLANGUAGE needs to be corrected, see Scintilla5Migration.html - just commented out: SCI_LOADLEXERLIBRARY Fix #10504, close #11419
45 lines
877 B
Plaintext
45 lines
877 B
Plaintext
{1}% Examples of each style 0..8 except for SCE_MATLAB_COMMAND(2) which has a line ending bug{0}
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{1}% White space=0{0}
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{1}%{0}
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{1}% Comment=1{0}
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{1}% Line comment{0}
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{1}% Next line is comment in Ocatve but not Matlab{0}
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{1}# Octave comment{0}
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{1}%{
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Block comment.
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%}{0}
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{1}% Command=2{0}
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{1}%{
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Omitted as this places a style transiton between \r and \n
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!rmdir oldtests
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%}{0}
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{1}% Number=3{0}
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{3}33.3{0}
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{1}% Keyword=4{0}
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{4}global{0} {7}x{0}
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{1}% Single Quoted String=5{0}
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{5}'string'{0}
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{1}% Operator=6{0}
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{6}[{7}X{6},{7}Y{6}]{0} {6}={0} {7}meshgrid{6}(-{3}10{6}:{3}0.25{6}:{3}10{6},-{3}10{6}:{3}0.25{6}:{3}10{6});{0}
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{1}% Identifier=7{0}
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{7}identifier{0} {6}={0} {3}2{0}
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{1}% Double Quoted String=8{0}
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{8}"string"{0}
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{1}% This loop should fold{0}
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{4}for{0} {7}i{0} {6}={0} {3}1{6}:{3}5{0}
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{7}x{6}({7}i{6}){0} {6}={0} {3}3{0} {6}*{0} {7}i{6};{0}
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{4}end{0}
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